3.586 \(\int \frac {1}{x^4 (c+a^2 c x^2)^{3/2} \tan ^{-1}(a x)^2} \, dx\)

Optimal. Leaf size=135 \[ -\frac {a^2 \text {Int}\left (\frac {1}{x^2 \sqrt {a^2 c x^2+c} \tan ^{-1}(a x)^2},x\right )}{c}+\frac {\text {Int}\left (\frac {1}{x^4 \sqrt {a^2 c x^2+c} \tan ^{-1}(a x)^2},x\right )}{c}-\frac {a^3 \sqrt {a^2 x^2+1} \text {Si}\left (\tan ^{-1}(a x)\right )}{c \sqrt {a^2 c x^2+c}}-\frac {a^3}{c \sqrt {a^2 c x^2+c} \tan ^{-1}(a x)} \]

[Out]

-a^3/c/arctan(a*x)/(a^2*c*x^2+c)^(1/2)-a^3*Si(arctan(a*x))*(a^2*x^2+1)^(1/2)/c/(a^2*c*x^2+c)^(1/2)+Unintegrabl
e(1/x^4/arctan(a*x)^2/(a^2*c*x^2+c)^(1/2),x)/c-a^2*Unintegrable(1/x^2/arctan(a*x)^2/(a^2*c*x^2+c)^(1/2),x)/c

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Rubi [A]  time = 0.67, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {1}{x^4 \left (c+a^2 c x^2\right )^{3/2} \tan ^{-1}(a x)^2} \, dx \]

Verification is Not applicable to the result.

[In]

Int[1/(x^4*(c + a^2*c*x^2)^(3/2)*ArcTan[a*x]^2),x]

[Out]

-(a^3/(c*Sqrt[c + a^2*c*x^2]*ArcTan[a*x])) - (a^3*Sqrt[1 + a^2*x^2]*SinIntegral[ArcTan[a*x]])/(c*Sqrt[c + a^2*
c*x^2]) + Defer[Int][1/(x^4*Sqrt[c + a^2*c*x^2]*ArcTan[a*x]^2), x]/c - (a^2*Defer[Int][1/(x^2*Sqrt[c + a^2*c*x
^2]*ArcTan[a*x]^2), x])/c

Rubi steps

\begin {align*} \int \frac {1}{x^4 \left (c+a^2 c x^2\right )^{3/2} \tan ^{-1}(a x)^2} \, dx &=-\left (a^2 \int \frac {1}{x^2 \left (c+a^2 c x^2\right )^{3/2} \tan ^{-1}(a x)^2} \, dx\right )+\frac {\int \frac {1}{x^4 \sqrt {c+a^2 c x^2} \tan ^{-1}(a x)^2} \, dx}{c}\\ &=a^4 \int \frac {1}{\left (c+a^2 c x^2\right )^{3/2} \tan ^{-1}(a x)^2} \, dx+\frac {\int \frac {1}{x^4 \sqrt {c+a^2 c x^2} \tan ^{-1}(a x)^2} \, dx}{c}-\frac {a^2 \int \frac {1}{x^2 \sqrt {c+a^2 c x^2} \tan ^{-1}(a x)^2} \, dx}{c}\\ &=-\frac {a^3}{c \sqrt {c+a^2 c x^2} \tan ^{-1}(a x)}-a^5 \int \frac {x}{\left (c+a^2 c x^2\right )^{3/2} \tan ^{-1}(a x)} \, dx+\frac {\int \frac {1}{x^4 \sqrt {c+a^2 c x^2} \tan ^{-1}(a x)^2} \, dx}{c}-\frac {a^2 \int \frac {1}{x^2 \sqrt {c+a^2 c x^2} \tan ^{-1}(a x)^2} \, dx}{c}\\ &=-\frac {a^3}{c \sqrt {c+a^2 c x^2} \tan ^{-1}(a x)}+\frac {\int \frac {1}{x^4 \sqrt {c+a^2 c x^2} \tan ^{-1}(a x)^2} \, dx}{c}-\frac {a^2 \int \frac {1}{x^2 \sqrt {c+a^2 c x^2} \tan ^{-1}(a x)^2} \, dx}{c}-\frac {\left (a^5 \sqrt {1+a^2 x^2}\right ) \int \frac {x}{\left (1+a^2 x^2\right )^{3/2} \tan ^{-1}(a x)} \, dx}{c \sqrt {c+a^2 c x^2}}\\ &=-\frac {a^3}{c \sqrt {c+a^2 c x^2} \tan ^{-1}(a x)}+\frac {\int \frac {1}{x^4 \sqrt {c+a^2 c x^2} \tan ^{-1}(a x)^2} \, dx}{c}-\frac {a^2 \int \frac {1}{x^2 \sqrt {c+a^2 c x^2} \tan ^{-1}(a x)^2} \, dx}{c}-\frac {\left (a^3 \sqrt {1+a^2 x^2}\right ) \operatorname {Subst}\left (\int \frac {\sin (x)}{x} \, dx,x,\tan ^{-1}(a x)\right )}{c \sqrt {c+a^2 c x^2}}\\ &=-\frac {a^3}{c \sqrt {c+a^2 c x^2} \tan ^{-1}(a x)}-\frac {a^3 \sqrt {1+a^2 x^2} \text {Si}\left (\tan ^{-1}(a x)\right )}{c \sqrt {c+a^2 c x^2}}+\frac {\int \frac {1}{x^4 \sqrt {c+a^2 c x^2} \tan ^{-1}(a x)^2} \, dx}{c}-\frac {a^2 \int \frac {1}{x^2 \sqrt {c+a^2 c x^2} \tan ^{-1}(a x)^2} \, dx}{c}\\ \end {align*}

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Mathematica [A]  time = 7.01, size = 0, normalized size = 0.00 \[ \int \frac {1}{x^4 \left (c+a^2 c x^2\right )^{3/2} \tan ^{-1}(a x)^2} \, dx \]

Verification is Not applicable to the result.

[In]

Integrate[1/(x^4*(c + a^2*c*x^2)^(3/2)*ArcTan[a*x]^2),x]

[Out]

Integrate[1/(x^4*(c + a^2*c*x^2)^(3/2)*ArcTan[a*x]^2), x]

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fricas [A]  time = 0.44, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {\sqrt {a^{2} c x^{2} + c}}{{\left (a^{4} c^{2} x^{8} + 2 \, a^{2} c^{2} x^{6} + c^{2} x^{4}\right )} \arctan \left (a x\right )^{2}}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^4/(a^2*c*x^2+c)^(3/2)/arctan(a*x)^2,x, algorithm="fricas")

[Out]

integral(sqrt(a^2*c*x^2 + c)/((a^4*c^2*x^8 + 2*a^2*c^2*x^6 + c^2*x^4)*arctan(a*x)^2), x)

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giac [A]  time = 0.00, size = 0, normalized size = 0.00 \[ \mathit {sage}_{0} x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^4/(a^2*c*x^2+c)^(3/2)/arctan(a*x)^2,x, algorithm="giac")

[Out]

sage0*x

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maple [A]  time = 4.27, size = 0, normalized size = 0.00 \[ \int \frac {1}{x^{4} \left (a^{2} c \,x^{2}+c \right )^{\frac {3}{2}} \arctan \left (a x \right )^{2}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/x^4/(a^2*c*x^2+c)^(3/2)/arctan(a*x)^2,x)

[Out]

int(1/x^4/(a^2*c*x^2+c)^(3/2)/arctan(a*x)^2,x)

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maxima [A]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{{\left (a^{2} c x^{2} + c\right )}^{\frac {3}{2}} x^{4} \arctan \left (a x\right )^{2}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^4/(a^2*c*x^2+c)^(3/2)/arctan(a*x)^2,x, algorithm="maxima")

[Out]

integrate(1/((a^2*c*x^2 + c)^(3/2)*x^4*arctan(a*x)^2), x)

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mupad [A]  time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {1}{x^4\,{\mathrm {atan}\left (a\,x\right )}^2\,{\left (c\,a^2\,x^2+c\right )}^{3/2}} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(x^4*atan(a*x)^2*(c + a^2*c*x^2)^(3/2)),x)

[Out]

int(1/(x^4*atan(a*x)^2*(c + a^2*c*x^2)^(3/2)), x)

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sympy [A]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{x^{4} \left (c \left (a^{2} x^{2} + 1\right )\right )^{\frac {3}{2}} \operatorname {atan}^{2}{\left (a x \right )}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x**4/(a**2*c*x**2+c)**(3/2)/atan(a*x)**2,x)

[Out]

Integral(1/(x**4*(c*(a**2*x**2 + 1))**(3/2)*atan(a*x)**2), x)

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